Asked by jason
write the standard form equation of the parabola with vertex (-2,-2) that goes through point (-1,0)
y= a (x-b)^2 + c
b has to be -2, that gives the shift to the left.
y=a( x+2)^2 + c
when x=-2, y=-2, that makes c -2
y=a( x+2)^2 -2
finally, put the point -1,0 in to find a.
y= a (x-b)^2 + c
b has to be -2, that gives the shift to the left.
y=a( x+2)^2 + c
when x=-2, y=-2, that makes c -2
y=a( x+2)^2 -2
finally, put the point -1,0 in to find a.