Asked by ayonna

Write the standard form of the equation of the circle x^2+y^2+4x-2y-20=0. Find the center and radius.
How do I do this? pleaaase help.

Answers

Answered by Knights
complete square:

(x+2)^2+(y-1)^2 = 20

Then minus 2^2+1^2 = 5, so add 5 to the 20

we get (x+2)^2+(y-1)^2 = 25

sqrt 25 = 5

so, 5 is the radius

the center is at (x+2)^2 = 0

(y-1)^2 = 0

so x = -2

y = 1

so the center is at (-2,1)
Answered by ayonna
thank you so much! ;)
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