Asked by Anonymous
                Write the standard form of the equation of a circle that passes through the points at (0,8) (8,0) and (16,8). Then identify the center and radius of the circle.
(x-8)^2 + (y-8)^2 = 64
(x^2 / 64) + (y^2 / 64) = 64
center=(8,8)
radius=8
I got it wrong don't know how
            
        (x-8)^2 + (y-8)^2 = 64
(x^2 / 64) + (y^2 / 64) = 64
center=(8,8)
radius=8
I got it wrong don't know how
Answers
                    Answered by
            Anonymous
            
    (x-8)^2 + (y-8)^2 = 64
fine
(x^2 / 64) + (y^2 / 64) = 64
but where did you get this??????
center=(8,8)
fine
radius=8
fine
    
fine
(x^2 / 64) + (y^2 / 64) = 64
but where did you get this??????
center=(8,8)
fine
radius=8
fine
                    Answered by
            bobpursley
            
    You will have to write the equation 
(x-h)^2+(y-k)^2=r^2
for the three sets of points given. Then solve for h, k, r
It is ugly but solvable.
    
(x-h)^2+(y-k)^2=r^2
for the three sets of points given. Then solve for h, k, r
It is ugly but solvable.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.