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Physics: an elastic cord can be stretched to its elastic limit by a load of 2N.if a 35cm length of the cord is extended 0.6cm b...Asked by Paul lazarus
An elastic cord can be stretched to it's elastic limit by a load of 2n.if a 35cm length of the cord is extended 0.6cm by a force of 0.5n.what will be the length of the cord when the stretching force is2.5n
Answers
Answered by
Henry
K = 0.5N/0.0.6cm = 0.833 N/cm.
Length = 35 + 2N*1cm/0.833N = 37.40 cm.
Increasing the force above 2N do
not increase length further.
Length = 35 + 2N*1cm/0.833N = 37.40 cm.
Increasing the force above 2N do
not increase length further.
Answered by
amy
the ans is 352.8cm
Answered by
Aka
Henry is correct
Answered by
Oguntuga folajimi
It cannot be determined from the data given
Answered by
Daniel
Pls for the length, am not sure you calculated well
Answered by
Miracle
Pls i hope this answer is the correct one plz
Answered by
Anonymous
It cannot be determined at all
Answered by
Favour
What about the 2.5N
Answered by
cherish
i dont understand how u got to that answer 37.40
Answered by
dammy
pls amy show ur workings๐ฅบ๐ฅบ๐
Answered by
dammy
anybody should snd d workings with d answer
Answered by
joseph
it cannot be determined from the given data
Answered by
Anonymous
8.33
Answered by
Margaa
Cannot be determined from the data given.
Answered by
Marga
Cannot be determined from the data given.
Answered by
Oluwaseyi Victor Taiwo
Pls is dat the correct answer ๐๐๐๐
Answered by
Faith Eze.
Cannot be determined with the give data.
Answered by
Anonymous
Dumb
Answered by
Uzoma
Already, the spring has reached it's elastic limit at 2N so increasing the stretching force to 2.5N will not yield any good result further. So I think the correct answer is that the length can not be determined
Answered by
Ajah
The answer is 2000000000000000000000000000000000000000000000000000000000000004000000000000000000000000000000000000003000000000000009999900/00000000000000984747473+4+483;32828+33+37373737337838228(23++373-37374-37374+3737373737373373773737374474747474747474743737382929291001012982733773737373382829191910101018272626268283849494949949484(44!448448848483883939392928283+37373737337377374849494949484747447473882822+2+2(2(2828387337737373737377338373737733733738389220020100191711+3-3+37377373373737373737. I hope you got the answer above.
Answered by
Adeola oluwadarasimi
Pls for the length,am not sure you calculated it well
Answered by
Damian Anita
It cannot be determined from the data given
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