Asked by Ayo
an eiastic cord can be stretched to its elastic limit by a load of 2N.if a 35cm length of the cord is extended 0.6cm by a force of 0.5N,what will be the length of the cord when the stretching force is 2.5cm.
Answers
Answered by
bobpursley
force is direcdtly proportional to lenght
f2/f1=x2/x1 where x is stretch
F2=.5*2.5/.6
F2=about 2 N
f2/f1=x2/x1 where x is stretch
F2=.5*2.5/.6
F2=about 2 N
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