Question

A block of mass m=25 kg is hung by a massless rope of length L=1.90 m from the ceiling of an elevator. The elevator has a downward acceleration of a=2.20 m/s^2. When the pendulum is set in a small amplitude oscillation, the period T of the pendulum is:

A) 2.50s
B) 3.14s
C) 1.57s
D) 4.31s
E) 1.86s

I am trying to use the pendulum equation of T=2pi*squareroot(L/g). But this is not working and I do not know how to use the acceleration that was given in the problem or if I need to.

Answer 1

T=2pi*sqrt[L/(g-a)]
B) 3.14