Question
A Mass Of 2.0kg Is Hung Off A Spring,which Extends 2cm. Determine The Energy Stored In The Spring.
Answers
Damon
assume g = 9.8 m/s^2
F = -k x
2 * 9.8 = k * .02
k = 980 Newtons
then
potential energy = U = (1/2) k x^2 = (1/2)(980)(.02)^2 Joules
F = -k x
2 * 9.8 = k * .02
k = 980 Newtons
then
potential energy = U = (1/2) k x^2 = (1/2)(980)(.02)^2 Joules
Silesh
Physics
Aysha
Your answer is correct but you must approximate the gravity from 9.8 into 10m/s*2
Dawit
Your answer is correct but you must approximate the gravity from 9.8 into 10m/s^2
Abdulmejid
Why assume gravity
Due to acceleration
Due to acceleration
Samrawit
Your answer is correct but why is you say F=-kx