Question

When a 4.48 kg mass is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.68 cm.

How much work must an external agent do to stretch the spring 3.96 cm from its unstretched position?

Oct 31, 2009

bobpursley

from the mass (remember mg is weight), find the spring constant.

Work=1/2 kx^2

Oct 31, 2009

128.45

Nov 2, 2011

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