Asked by briana wiliams
A block of mass 0.433kg is hung from a vertical spring and allow it to reach equilibrium rest. As a result the spring is stretched by 0.603m. Find the spring constant.
Answers
Answered by
bobpursley
force= kx
.433*g=k(.603) solve for k in Newtons/meter
.433*g=k(.603) solve for k in Newtons/meter
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