Question

A 26.8 mL sample of a solution of RbOH is neutralized by 15.71 mL of a 1.918 M solution of HBr. What is the molarity of the RbOH solution?

Answer 1

RbOH + HBr ==> RbBr + H2O

mols HBr = M x L = ?
mols RbOH = mols HBr
M RbOH = mols HBr/L HBr = ?

Answer 2

Also, because the reaction is a 1:1 rxn ratio, it is useful to apply (Molarity x Volume)Acid = (Molarity x Volume)Base => (1.918M)(15.71ml) = M(base) x (26.8ml). Solve for Molarity of base (RbOH). The volumes can be left in ml as both sides of the equation contain mls, they will cancel and only Molarity remains.