Asked by Angel
A 893 g sample of a solution of the solute (CH3)2CO in the solvent C4H8O that has a concentration of 28.6 pph(parts per hundred) by mass (CH3)2CO is available. Calculate the amount (g) of acetone that is present in the sample.
Molar Mass (g/mol)
(CH3)2CO 58.05
C4H8O 72.12
Density (kg/m3):
(CH3)2CO 789.9
C4H8O 889.2
Name/Formula:
acetone
(CH3)2CO
tetrahydrofuran
C4H8O
Molar Mass (g/mol)
(CH3)2CO 58.05
C4H8O 72.12
Density (kg/m3):
(CH3)2CO 789.9
C4H8O 889.2
Name/Formula:
acetone
(CH3)2CO
tetrahydrofuran
C4H8O
Answers
Answered by
DrBob222
Would that be 893 x 0.286 = ??
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