Asked by amber
a 340.4 ml sample of solution contains 27.4 g of cacl2. calcuate the molar concentration of calcium ion in this solution.
this is what i did
27.4(110.98) =.247mol
.247mol/34.4L=.726Mcacl2
is this correct?
this is what i did
27.4(110.98) =.247mol
.247mol/34.4L=.726Mcacl2
is this correct?
Answers
Answered by
bobpursley
ARRRRGGGGG.
moles=27.4g/(110.98) =.247mol
molarity=.247/.3404liters=.726Moles/liter
moles=27.4g/(110.98) =.247mol
molarity=.247/.3404liters=.726Moles/liter
Answered by
amber
whats arrgg mean?
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