Asked by Reed
Suppose the 480 lb pile driver that drops 20 ft drives the pile 2 in. every time it strikes the pile. What is the average resisting force of the ground where the pile is driven?
Answers
Answered by
jon
45
Answered by
bobpursley
I am wondering about your instructor, using these obsolite English units, lb, in,
I would do it this way:
energy in the pile=resistive force*distancetmoved
masspile*g*height=F*drivenmove
solve for F, but I would do it in SI units.
I would do it this way:
energy in the pile=resistive force*distancetmoved
masspile*g*height=F*drivenmove
solve for F, but I would do it in SI units.
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