Asked by Kimberly
The pile driver struck the piling with a speed of 20 m/s. At what height did the pile driver hammer have to be lifted for it to fall freely and attain that speed before striking the piling?
Show steps please!!!
Show steps please!!!
Answers
Answered by
bobpursley
potential energy at start=Kenergy at end
mgh=1/2 m v^2
h= 1/2 v^2/g
mgh=1/2 m v^2
h= 1/2 v^2/g
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