Asked by Courtney
Find the equation of the line tangent to the curve y=(x^2+3)^1/2 that is perpendicular to the line 2x-y+7=0
Answers
Answered by
Steve
you want the tangent to have slope -1/2
y' = x/√(x^2+3)
so, where is that = -1/2 ?
Get the point and use the point-slope form of the line.
y' = x/√(x^2+3)
so, where is that = -1/2 ?
Get the point and use the point-slope form of the line.
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