Asked by anna
A projectile is launched from ground level at an angle of 45 degrees above the horizontal with a speed of 40m/s. It is aimed straight towards a high wall that is a horizontal distance of 120m away from the launch point.
a) How much time will the projectile spend in the air before it hits the wall?
b) At what hight above the ground level will the projectile hit the wall?
a) How much time will the projectile spend in the air before it hits the wall?
b) At what hight above the ground level will the projectile hit the wall?
Answers
Answered by
bobpursley
assume it hits wall.
distance=vh*time
120=40*cos45*time
time=30/cos45
hf=hi+vvi*timeinair-4.9 t^2
put in time t, and calculate hf.
vvi=40sin45
distance=vh*time
120=40*cos45*time
time=30/cos45
hf=hi+vvi*timeinair-4.9 t^2
put in time t, and calculate hf.
vvi=40sin45
Answered by
anna
is hi equal to zero?
Answered by
anna
Also time = 3/cos45 not 30
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