Asked by Fullmetal
An ice skater of mass (on frictionless ice) fires a bullet of mass 10 grams that leaves the barrel at 500 m/s (in the x-direction relative to the ground)
A) what is the recoil velocity of the skater relative to the ground?
B) how much work is done in the bullet by the exploding gunpowder?
A) what is the recoil velocity of the skater relative to the ground?
B) how much work is done in the bullet by the exploding gunpowder?
Answers
Answered by
Chanz
A) this is conservation of momentum, which is zero in both cases. Unfortunately you neglected to give the skater's mass.
mv (skater) = mv (bullet)
watch units.
B) W = KE of bullet = 1/2(.001)500^2
mv (skater) = mv (bullet)
watch units.
B) W = KE of bullet = 1/2(.001)500^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.