Question

An ice skater with a mass of 60.0kg is moving at 20.0 m/s coasts to a halt in 2.00×10^2m on a smooth ice surface. What is the coefficient of friction between the ice and the skates?

Answer 1

KE of skater=work done by ice
1/2(60)20^2=mu*60*9.8*200
solve for mu