Asked by zinhle
a skater with a mass of 65kg,reaches the bottom of a ramp ,2.5 metres high ,going at 27km.h-1.
calculate his kinetic energy as he reaches the ramp
calculate how fast he is going by the time he reaches the top of the ramp
calculate his kinetic energy as he reaches the ramp
calculate how fast he is going by the time he reaches the top of the ramp
Answers
Answered by
Damon
I am sure that you could have done this problem three times in the time you spent typing it.
v = 27 km/hr * 1000m/km * 1 hr/3600 s
Ke = (1/2) m v^2
loss of energy = m g h
Ke at top = Ke at bottom i energy lost
(1/2) m u^2 = Ke at top
v = 27 km/hr * 1000m/km * 1 hr/3600 s
Ke = (1/2) m v^2
loss of energy = m g h
Ke at top = Ke at bottom i energy lost
(1/2) m u^2 = Ke at top
Answered by
Damon
Ke at top = Ke at bottom - energy lost
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