Asked by Bri
A 5-kg box is placed on a frictionless ramp which is sloped at a 30-degree angle from horizontal. A rope attaches the box to a post further up the ramp. How much tension is in the rope?
Answers
Answered by
Henry
M*g = 5*9.8 = 49 N. = Wt. of the box.
Fp = 49*sin30 = 24.5 N. = Force parallel t0 the incline.
T = Fp = 24.5 N.
Fp = 49*sin30 = 24.5 N. = Force parallel t0 the incline.
T = Fp = 24.5 N.
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