Question
A 42-kg box slides down a frictionless inclined plane. The angle of the inclined plane is 34.0 degrees. The distance from the box to the bottom of the inclined plane is 3 m. Draw the free body diagram of the force vectors acting on the box. Determine:
a. The weight of the box
b. the normal force acting on the box
c. the acceleration of the box down the incline
d. the velocity of the box a the bottom of the inclined plane
e. the time it took for the box to slide to the bottom of the inclined plane
a. The weight of the box
b. the normal force acting on the box
c. the acceleration of the box down the incline
d. the velocity of the box a the bottom of the inclined plane
e. the time it took for the box to slide to the bottom of the inclined plane
Answers
a 42*9.81
b 42*9.81 cos 34
c force down slope = 42*9.81 * sin 34
so
a = 9.81 sin 34
d 3 = .5 (9.81*sin34) * t^2
t is answer to e
v = a t = 9.81 sin 34 *t
b 42*9.81 cos 34
c force down slope = 42*9.81 * sin 34
so
a = 9.81 sin 34
d 3 = .5 (9.81*sin34) * t^2
t is answer to e
v = a t = 9.81 sin 34 *t
A box weighing 20lb. is being pushed up an incline. If the angle of incline was 90° to the ground, what effort would be needed to push the mass?
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