a 42*9.81
b 42*9.81 cos 34
c force down slope = 42*9.81 * sin 34
so
a = 9.81 sin 34
d 3 = .5 (9.81*sin34) * t^2
t is answer to e
v = a t = 9.81 sin 34 *t
A 42-kg box slides down a frictionless inclined plane. The angle of the inclined plane is 34.0 degrees. The distance from the box to the bottom of the inclined plane is 3 m. Draw the free body diagram of the force vectors acting on the box. Determine:
a. The weight of the box
b. the normal force acting on the box
c. the acceleration of the box down the incline
d. the velocity of the box a the bottom of the inclined plane
e. the time it took for the box to slide to the bottom of the inclined plane
2 answers
A box weighing 20lb. is being pushed up an incline. If the angle of incline was 90° to the ground, what effort would be needed to push the mass?
2 answers