Asked by Ashley

Cos(-Θ) = Sqrt2/3
SinΘ<0

What is the value of sin Θ?

A. Sqrt7/3
B.-sqrt7/3
C.sqrt14/7
D.-sqrt14/2

I think it's C

Answers

Answered by Scott
sin^2 + cos^2 = 1

sin^2 + 2/9 = 1

sin^2 = 7/9

sin = ±√7 / 3
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