To determine the sine ratio given that \(\cos 0 = \frac{\sqrt{2}}{5}\), we can use the Pythagorean identity:
\[ \sin^2 \theta + \cos^2 \theta = 1 \]
First, we substitute \(\cos 0\) into the identity:
\[ \sin^2 0 + \left(\frac{\sqrt{2}}{5}\right)^2 = 1 \]
Calculating \(\left(\frac{\sqrt{2}}{5}\right)^2\):
\[ \left(\frac{\sqrt{2}}{5}\right)^2 = \frac{2}{25} \]
Now, substituting this into the Pythagorean identity:
\[ \sin^2 0 + \frac{2}{25} = 1 \]
Now, isolate \(\sin^2 0\):
\[ \sin^2 0 = 1 - \frac{2}{25} \]
We can express 1 as \(\frac{25}{25}\):
\[ \sin^2 0 = \frac{25}{25} - \frac{2}{25} = \frac{23}{25} \]
Now, take the square root of both sides to find \(\sin 0\):
\[ \sin 0 = \sqrt{\frac{23}{25}} = \frac{\sqrt{23}}{5} \]
None of the given options (a. \(1\), b. \(\frac{1}{2}\), c. \(\frac{\sqrt{2}}{2}\), d. \(\frac{\sqrt{3}}{2}\)) match \(\frac{\sqrt{23}}{5}\). Therefore, it appears that none of the provided options are correct based on the values given.