Question

(sinθ+1)/(1-sinθ) =(tanθ+secθ)²

Answer 1

(1+sinθ)/(1-sinθ)
= (1+sinθ)/(1-sinθ) * (1+sinθ)/(1+sinθ)
= (1+sinθ)^2 / (1-sin^2θ)
= (1+2sinθ+sin^2θ)/cos^2θ
= sec^2θ + 2secθtanθ + tan^2θ
= (secθ+tanθ)^2