Asked by manpreet
(sinθ+1)/(1-sinθ) =(tanθ+secθ)²
Answers
Answered by
Steve
(1+sinθ)/(1-sinθ)
= (1+sinθ)/(1-sinθ) * (1+sinθ)/(1+sinθ)
= (1+sinθ)^2 / (1-sin^2θ)
= (1+2sinθ+sin^2θ)/cos^2θ
= sec^2θ + 2secθtanθ + tan^2θ
= (secθ+tanθ)^2
= (1+sinθ)/(1-sinθ) * (1+sinθ)/(1+sinθ)
= (1+sinθ)^2 / (1-sin^2θ)
= (1+2sinθ+sin^2θ)/cos^2θ
= sec^2θ + 2secθtanθ + tan^2θ
= (secθ+tanθ)^2
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