Asked by bob
if -sinθ= 0.5736 and 90°≤θ≤180° , find the value of θ
Answers
Answered by
Reiny
-sinθ= 0.5736
sinθ= - 0.5736
90°≤θ≤180° <----- you are in quadrant II, in that quad the sine is positive,
so there is no solution to your equation
if you meant
sinθ= 0.5736
the angle in standard position would be 35.002° or appr 35°
so θ = 180° - 35° = 145°
sinθ= - 0.5736
90°≤θ≤180° <----- you are in quadrant II, in that quad the sine is positive,
so there is no solution to your equation
if you meant
sinθ= 0.5736
the angle in standard position would be 35.002° or appr 35°
so θ = 180° - 35° = 145°
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