Asked by lisa

A brick is thrown upward from the top of a building at an angle of 35° to the horizontal and with an initial speed of 15 m/s. If the brick is in flight for 2.7 s, how tall is the building? in (m)
Answered by vicky
y=1/2gt^2+vsin (35)

y=1/2×10×2.7^2+15×sin (35)

y=30.02m
Answered by Henry
See previous post: Thu, 2-4-16, 10:47 PM.
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