Question
Suppose that a constant force is applied to an object. Newton's Second Law of Motion states that the acceleration of the object varies inversely with its mass. A constant force acting upon an object with mass 12 kg produces an acceleration of 2m/s^2. The acceleration of another object produced by the same force is 3m/s^2. What is the mass of this object?
Answers
a = k/m^2 , where k is constant
given: when a=2 m/s^2, m = 12 kg
2 = k/12^2
k = 288
a = 288/m^2
so when a = 3
3 = 288/m^2
3m^2 = 288
m^2 = 96
m= appr 9.8
the mass is appr 9.8 Kg
or , just use a ratio
2/3 = m^2/12^2
3m^2 = 288
etc, same as above
given: when a=2 m/s^2, m = 12 kg
2 = k/12^2
k = 288
a = 288/m^2
so when a = 3
3 = 288/m^2
3m^2 = 288
m^2 = 96
m= appr 9.8
the mass is appr 9.8 Kg
or , just use a ratio
2/3 = m^2/12^2
3m^2 = 288
etc, same as above
Thank you!
welcome
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