Question

Solve by completing the square ( find the vertex only)

K^2-18k+50=0

M^2+500m+100=0

Answer 1

Recall that (x-a)^2 = x^2-2ax+a^2


k^2-18k+50 = 0
k^2-18k = -50

Now, you want half of the coefficient of k and square it, so you have a perfect square. Then, to keep things equal, you have to add it to the right side as well.

k^2-18k+81 = -50+81
(k-9)^2 = 31
k-9 = ±√31
k = 9±√31

Now do the other the same way.

Answer 2

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