Asked by Aliyah
Solve by completing the square: A rectangular patio has a length of (x + 6) m, a width of (x + 8) m, and a total area of 400 m2. Find the dimensions to the nearest tenth.
Please help me with this math problem. Thanks so much.
Please help me with this math problem. Thanks so much.
Answers
Answered by
Aliyah
m^2*
Answered by
Steve
(x+6)(x+8) = 400
x^2+14x+48 = 400
x^2+14x+49 = 401
(x+7)^2 = 401
x+7 = ±√401
x = -7±√401
we want a positive value for x+6, so x=-7+√401 ≈13.025
So the dimensions are 19.025 by 21.025
Note that (x+6)(x+8) = (x+7-1)(x+7+1) = (x+7)^2 - 1^2 as seen above
x^2+14x+48 = 400
x^2+14x+49 = 401
(x+7)^2 = 401
x+7 = ±√401
x = -7±√401
we want a positive value for x+6, so x=-7+√401 ≈13.025
So the dimensions are 19.025 by 21.025
Note that (x+6)(x+8) = (x+7-1)(x+7+1) = (x+7)^2 - 1^2 as seen above
Answered by
Kit-Kat
I need help too
Answered by
What
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