Asked by David

Solve by completing the square: x^2+3x-28=0

12 years ago

Answered by Steve

x^2+3x-28 = 0
x^2+3x = 28
x^2 + 2(3/2)x + (3/2)^2 = 28 + (3/2)^2
(x + 3/2)^2 = 121/4 = (11/2)^2
x + 3/2 = ± 11/2
x = -3/2 ± 11/2
x = -7,4

12 years ago

Answered by David

Thanks steve

12 years ago

Answered by buzz

wow thx

4 years ago

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