Ask a New Question
Search
Asked by
David
Solve by completing the square: x^2+3x-28=0
Answers
Human Answers
3
AI Answers
0
Answered by
Steve
x^2+3x-28 = 0
x^2+3x = 28
x^2 + 2(3/2)x + (3/2)^2 = 28 + (3/2)^2
(x + 3/2)^2 = 121/4 = (11/2)^2
x + 3/2 = ± 11/2
x = -3/2 ± 11/2
x = -7,4
Answered by
David
Thanks steve
Answered by
buzz
wow thx
There are no AI answers yet. The ability to request AI answers is coming soon!
Related Questions
Related
Solve by completing the square. x^2 +20x - 44 = 0 (1 point) O X =-22, x = 2 O X = -10, X = 5 O...
Solve by completing the square. x2+20x−44=0 (1 point) Responses x=−5, x=10 x=−5, x=10...
Solve by completing the square X^3 - 8x + 4 = -3
Completing the Square Solve each equation by using the Square Root Property. Round to the nearest h...
solve by completing the square. x^2-8x+4=-3 x^2-8x=____ x^2-8x___=____ (x___ ___)^2 = ___ (x__...
solve by completing the square x^2-3x=4 please show work
Solve by completing the square x^2+3/2x=3 What is the solution? x=
Solve by completing the square 12x^2+11x=5
Solve by completing the square y=2x^2-3x+7
Solve by completing the square x^2+3/2x=3