Solve for d D(t)= -8cos (pi(t)/30)+8

Prove: cos4x = 8cos^4x - 8cos^2x + 1 My Attempt: RS: = 4cos^2x (2cos^2x - 1) + 1 = 4 cos^2x (...

Prove that cos4x=8cos^4x-8cos^2x+1 so I'm guessing you begin with the left side cos4x=cos2(2x)...

Why does 1/8cos(2y+6) become 1/8cos(arcsinx/4)?

1. 4sin^2x=3tan^2x-1 2. 8cos^2x-4cos^4x=3 3. 3secx-cosx=2

y=8cos((1/2)x)+10 dy/dx = -4sin((1/2)x) What is the maximum slope from 0 - 4(pi)? I tried equ...

f(x)=5sin^2x-8cos^5x [0,5 1.5]

Which are the solutions to 8cos^2 theta-3cos theta=0, 0 degrees is less than or equal to theta which...

Solve 8cos(5x) = 4 for the three smallest positive solutions

Show that cos 4 alpha =8cos^4alpha - 8cos^2alpha + 1

Show that Cos 4¤=8cos^4¤ - 8cos^2 + 1

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