Asked by Melissa
Evaluate the series 12.1 + 13 +13.9 +...+ 32.8.
Answers
Answered by
Reiny
looks like an AS with a = 12.1 , d = .9
what is the term number of 32.8 ?
a + (n-1)d = termn
12.1 + (n-1)(.9) = 32.8
.9n- .9 = 20.7
.9n =21.6
n = 24
sum(24) = 12(first + last)
= 12(12.1 + 32.8) = 538.8
check my arithmetic
what is the term number of 32.8 ?
a + (n-1)d = termn
12.1 + (n-1)(.9) = 32.8
.9n- .9 = 20.7
.9n =21.6
n = 24
sum(24) = 12(first + last)
= 12(12.1 + 32.8) = 538.8
check my arithmetic