Asked by monica
Use series to evaluate the limit.
limit as x approach 0
[1-cos(5x)]/[1+5x-e^(5x)]
limit as x approach 0
[1-cos(5x)]/[1+5x-e^(5x)]
Answers
Answered by
Anonymous
(5x)^2/2 / 5x = 2.5 x
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