Asked by Kate
                Evaluate the geometric Series or state that it diverges 
lower bound k= 1 upper bound = infinity
E (sum symbol) E 5(-1/6)^(5k)
I know it converges but im not sure to what
            
        lower bound k= 1 upper bound = infinity
E (sum symbol) E 5(-1/6)^(5k)
I know it converges but im not sure to what
Answers
                    Answered by
            Steve
            
    a = 5(-1/6)^5
Note that (-1/6)^(5k) = ((-1/6)^5)^k, so
r = (-1/6)^5
S = a/(1-r) = (5(-1/6)^5)/(1-(-1/6)^5) = -5/7777
    
Note that (-1/6)^(5k) = ((-1/6)^5)^k, so
r = (-1/6)^5
S = a/(1-r) = (5(-1/6)^5)/(1-(-1/6)^5) = -5/7777
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