Asked by Kate
Evaluate the geometric Series or state that it diverges
lower bound k= 1 upper bound = infinity
E (sum symbol) E 5(-1/6)^(5k)
I know it converges but im not sure to what
lower bound k= 1 upper bound = infinity
E (sum symbol) E 5(-1/6)^(5k)
I know it converges but im not sure to what
Answers
Answered by
Steve
a = 5(-1/6)^5
Note that (-1/6)^(5k) = ((-1/6)^5)^k, so
r = (-1/6)^5
S = a/(1-r) = (5(-1/6)^5)/(1-(-1/6)^5) = -5/7777
Note that (-1/6)^(5k) = ((-1/6)^5)^k, so
r = (-1/6)^5
S = a/(1-r) = (5(-1/6)^5)/(1-(-1/6)^5) = -5/7777