Asked by Asemahle
Given the geometric series 256+p+64-32+
Determine the value of p
Determine the value of p
Answers
Answered by
Bosnian
128
Obviously the common ratio
r = 1 / 2 = 0.5
256 ∙ 0.5 = 128
128 ∙ 0.5 = 64
64∙ 0.5 = 32
Obviously the common ratio
r = 1 / 2 = 0.5
256 ∙ 0.5 = 128
128 ∙ 0.5 = 64
64∙ 0.5 = 32
Answered by
Reiny
Actually the -32 tells us p = -128 with a common ratio of -1/2
64/p = -32/64
-32p = 4096
p = -128
64/p = -32/64
-32p = 4096
p = -128
Answered by
Sakhï
T2/T1 = T3/T2
P/256 = 64/P
Then you cross multiply
P squared = 16 384
Put square root on both sides
P = -128
Note that the answer of the square root has +/-
P/256 = 64/P
Then you cross multiply
P squared = 16 384
Put square root on both sides
P = -128
Note that the answer of the square root has +/-
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.