Question
A geometric series has t1 = 100 and t2 = 90.
Find the number to which Sn converges as n gets very large.
Find the number to which Sn converges as n gets very large.
Answers
Steve
t2/t1 = 0.9
sum = 100/(1-.9) = 100/.1 = 1000
sum = 100/(1-.9) = 100/.1 = 1000