Use the following information to find Hf of butanol [C4H9OH(l)].

C4H9OH(l) + 6 O2(g) 4 CO2(g) + 5 H2O(g)


Hcomb = -2712.9

Hf of CO2(g) = -393.5 kJ/mol

Hf of H2O(g) = -241.8 kJ/mo

1 answer

This looks like a homework dump. No tutor here will do your homework for you. If you do not know how to solve these problems, say so, and we might be able to help you learn how.