Asked by mara
Use the following information to find Hf of butanol [C4H9OH(l)].
C4H9OH(l) + 6 O2(g) 4 CO2(g) + 5 H2O(g)
Hcomb = -2712.9
Hf of CO2(g) = -393.5 kJ/mol
Hf of H2O(g) = -241.8 kJ/mo
C4H9OH(l) + 6 O2(g) 4 CO2(g) + 5 H2O(g)
Hcomb = -2712.9
Hf of CO2(g) = -393.5 kJ/mol
Hf of H2O(g) = -241.8 kJ/mo
Answers
Answered by
Reed
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