Question

Given the following information, determine the 68.3 percent, 95.5 percent, and 99.7 percent confidence intervals.

overbar above X equals 4.33 comma SE sub m equals 3

I've looked at the table as recommended. I just do not understand this at all. I'm really lost on this and confused. Pick a confidence level, calculate Z score do this do that. I am so lost and desperate to at least have a clue as to how this needs to be done. Help me someone please!!???

besides telling me to look at the back of a book for a table, looking at it does nothing for me I am lost. I would appreciate it.

Answer 1

Somebody be so kind and brake this down to me, please it's for a test I need the help.

Answer 2

Mean = 4.33
SE 3
1- a = .683
a= 0.317
Za/2 = Z0.1585 = 1 z table
invNorm(0.1585) = 1

mean -+ Z *SE
4.33 -1(3), 4.33+1*3
(1.33, 7.33)

You can follow concept and you will get rest of your answer.

Answer 3

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability [(1-.95)/2] = Z = 1.96. You divide by 2, because you are considering both above and below.

95% = mean ± 1.96 SEm

The other percentages would be solved in the same way.