% = mean ± Z(SEm)
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (%/2) from the mean and its Z score. Substitute values into above equation and calculate.
If you don't have that table in the back of your text, try this:
https://www.google.com/search?client=safari&rls=en&q=z+scores+calculator&ie=UTF-8&oe=UTF-8
Given the following information, determine the 68.3 percent, 95.5 percent, and 99.7 percent confidence intervals.
overbar above X equals 4.33 comma SE sub m equals 3
I would appreciate it extremely if someone would help me figure this out. I honestly have no idea how to do this. Help please I am lost!
I noticed someone else posted this exact question and the answer was to look at the back of a table, however I have an electronic version which doesn't have it. Help please
1 answer