Asked by Sean
A man runs east 9.8 m/s for 11 s, stops for 6.9 s, then runs back (west) at 1.5 m/s for 1.2 s. What is the man's average velocity?
Answers
Answered by
bobpursley
velocity=displacement/time
displacement=9.8*11E-1.58*1.2E
time=11+6.9+1.2
displacement=9.8*11E-1.58*1.2E
time=11+6.9+1.2
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