Question
An athlete runs 2.76 km east, then turns south and runs another 0.85 km. What is the magnitude of his displacement?
Answers
Henry
2.76km[0o] + 0.85km[270o]
X = 2.76*Coso + 0.85*cos270 = 2.76 N.
Y = 2.76*sin0 + 0.85*sin270 =
Fr = sqrt(X^2+Y^2)
X = 2.76*Coso + 0.85*cos270 = 2.76 N.
Y = 2.76*sin0 + 0.85*sin270 =
Fr = sqrt(X^2+Y^2)