v(t) = dx/dt = u+at
Now go for it. I hope you have a value for a.
The position of a particle moving on a smooth horizontal floor is given as a function of time according to the equation x=ut+1/2at^2. At time t=0, the particle has the velocity u. Obtain an expression for the velocity as the function of time. Hence, find the value of this velocity after 8 seconds given that the initial velocity ,u, is 5.0m/s.
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I want the layout of the solution please
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