Ask a New Question

Question

If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t^2. Find the velocity when t = 1.
10 years ago

Answers

Damon
v = dy/dt = 34 - 32 t

if t = 1
v = 2
10 years ago

Related Questions

A ball is thrown from the top edge of a building with initial velocity components of 15m/s(up) verti... A ball is thrown from the top of a building. It's height (y) in feet at any given time (x) in second... A ball is thrown at 22m/s at 45 degrees to the horizontal. a fence 5 feet tall is located 100 meters... A ball is thrown into the air with an upward velocity of 32 ft/s. Its height h in feet after t secon... a ball is thrown into the air with an initial upward velocity of 60 ft/s. its height (h) in feet aft... A ball is thrown into the air from the edge of a 48-foot-high cliff so that it eventually lands on t... A ball is thrown into the air from the edge of a 48-foot-high cliff so that it eventually lands on t... A ball is thrown into the air from the edge of a 48-foot-high cliff so that it eventually lands on t...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use