Question

If a ball is thrown into the air with a velocity of 40 ft/s, its height in feet t seconds later is given by y = 40t − 16t^2.
Find the average velocity for the time period beginning when t = 2 and lasting for each of the following.

1) 0.5 seconds.

Answer 1

when t = 2, y = 40(2) - 16(4) = 16
when t = 2.5 , y = 40(2.5) - 16(2.5^2) = 0

avg velocity = (0-16)/(2.5-2) = -32 ft/s

Answer 2

-32