Asked by Amy
                The mass of a beaker is 5.333g. After 5.00 mL of a concentrated hydrochloric acid solution is pipetted into the beaker, the combined mass of the beaker and the hydrochloric acid sample is 11.229 g. From the data, what is the measured density of the hydrochloric solution? 
Can you please show me a step by step way to answer this. I have many other questions similar to this and a sample of how to complete this answer would help me solve the others.
Thank you!
            
        Can you please show me a step by step way to answer this. I have many other questions similar to this and a sample of how to complete this answer would help me solve the others.
Thank you!
Answers
                    Answered by
            Damon
            
    mass of acid = 11.299-5.333 grams
density = mass/volume
= (11.299 - 5.333) g / 5 mL
    
density = mass/volume
= (11.299 - 5.333) g / 5 mL
                    Answered by
            DrBob222
            
    I think you must be overthinking this problem.
11.229 g = mass HCl + empty beaker
-5.333 g = mass empty beaker
--------------------
?? = mass HCl
Then density HCl = mass HCl/volume HCl. The mass is given in the problem.
    
11.229 g = mass HCl + empty beaker
-5.333 g = mass empty beaker
--------------------
?? = mass HCl
Then density HCl = mass HCl/volume HCl. The mass is given in the problem.
                    Answered by
            Amy
            
    So the answer is: density= 1.1792g ? 
    
                    Answered by
            DrBob222
            
    No. You must have punched a wrong key somewhere.
    
                    Answered by
            Amy
            
    Can you show me the numbers I need to punch in? I am totally confused? 
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.