Question

The mass of a dry, 50 mL beaker is 49.135 g. The observed volume of water in a volumetric pipet is 20.00 mL. This water is transferred to the beaker and the combined mass of the water and the beaker is found to be 69.122 g. Given that the density of water at 24 degrees Celsius is 0.99732 g/mL, calculate:

a) The mass of water:

b) The actual volume of water in the beaker:

c)Percent error in the volume measurement:

Answer 1

Really need some help solving these please.

Answer 2

69.122 g = mass bkr + mass H2O
-49.135 = mass empty bkr
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a. xxxxxx = mass H2O

b. volume = mass/density = xxxx/0.99732

c. %error = [value of b/20]*100 = ?

Answer 3

You are too impatient. 15 minutes from the time you posted the first time to the second time is too little time to give an old guy like me time to type in the answer.

Answer 4

Thank you so much for your help.
I actually sent the second one because I realized I had forgotten to say please in the first one.

Answer 5

The second one was sent while I was typing the response. We're glad to have you use Jiskha. You're welcome to use our services anytime. I would have prefered that yu tell us what you didn't understand about the problem AND to tell us how you thought the problem might be worked.