Asked by Gela
A projectile is fired from a cliff 300 m high with an initial velocity of 400 m/s. If the firing angle is 30 degrees from the horizontal, compute the horizontal range of the projectile.
Answers
Answered by
Damon
Horizontal problem:
u = 400 cos 30 forever
range = u t
where t is the time from the vertical problem
Vertical problem:
Hi = 300 meters
Vi = 400 sin 30 = 200 m/s
v = Vi - 9.81 t
h = Hi + Vi t - 4.9 t^2
0 = 300 + 200 t - 4.9 t^2
solve that quadratic for t (the positive root, not the one that occurs inside the virtual cliff on the way up)
Use that time in the air in the horizontal problem to get range.
u = 400 cos 30 forever
range = u t
where t is the time from the vertical problem
Vertical problem:
Hi = 300 meters
Vi = 400 sin 30 = 200 m/s
v = Vi - 9.81 t
h = Hi + Vi t - 4.9 t^2
0 = 300 + 200 t - 4.9 t^2
solve that quadratic for t (the positive root, not the one that occurs inside the virtual cliff on the way up)
Use that time in the air in the horizontal problem to get range.
Answered by
Anonymous
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