If a projectile is fired with initial velocity of an angle 90° calculate

Question

I) time of flight
II)height
III) range of flight
Take g=9.8m/s-2

Answer 1

once you decide on the initial velocity v0, then
v = v0 - 9.8t
h = v0*t - 4.9t^2
i) find t when v=0 -- that is how long it takes to go up and stop. That is 1/2 the time of flight.
ii) find h(t) from (i)
(iii) range=0, since it comes back straight down