Asked by Miranda
A projectile is fired off a 35m cliff at 18m/s. what horizontal distance does the projectile travel before hitting the ground?
Answers
Answered by
Henry
h = 0.5g*t^2 = 35 m.
4.9t^2 = 35
t^2 = 7.143
Tf = 2.673 s. = Fall time.
D = Xo * Tf = 18m/s * 2.673s = 48.11 m.
4.9t^2 = 35
t^2 = 7.143
Tf = 2.673 s. = Fall time.
D = Xo * Tf = 18m/s * 2.673s = 48.11 m.
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