Asked by Mehrin Ali
A projectile is fired from the surface of the Earth with a speed of 200 meters per second at an angle of 30°
above the horizontal. If the ground is level, what is the maximum height reached by the projectile?
(A) 5 m (B) 10 m (C) 500 m (D) 1,000 m (E) 2,000 m
above the horizontal. If the ground is level, what is the maximum height reached by the projectile?
(A) 5 m (B) 10 m (C) 500 m (D) 1,000 m (E) 2,000 m
Answers
Answered by
Henry
Vo = 200m/s[30o]
Yo = 200*sin30 = 100 m/s.
Y^2 = Yo^2 + 2g*h
h = (Y^2-Yo^2)/2g
h=(0-100^2)/-20 = 500 m. g = -10 m/s^2
Yo = 200*sin30 = 100 m/s.
Y^2 = Yo^2 + 2g*h
h = (Y^2-Yo^2)/2g
h=(0-100^2)/-20 = 500 m. g = -10 m/s^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.